Stage times given to the peleton
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This is probably a newbie question, but I'll throw it out there anyway...
What are the specific rules for awarding finish times at the end of a stage? I know the peleton or,
a bunch sprint, gets the same time at the line as the first person of the group to cross. But in the
case of a strung out paceline or if you're in a smaller group off the back/front, how close do you
have to be to the person in front of you to get the same time as them?
I'm assuming, that, because the times go down to the second, you have to be within a second of the
bike in front of you (??) or is it bike lengths or something else...?
John
On 2 Aug 2003 12:45:57 -0700, FLBiker wrote:
>you have to be within a second of the bike in front of you (??)
Check.
"Ewoud Dronkert" <me@privacy.net> wrote in message
news:aj6oivgn68tup167lmmqsr9d1tlq8394s1@news.cis.dfn.de...
> On 2 Aug 2003 12:45:57 -0700, FLBiker wrote:
> >you have to be within a second of the bike in front of you (??)
>
> Check.
You know, the UCI rules are oddly silent on this. They say (2.3.040),
"All riders in a given bunch shall be credited with the same time when they cross the
finishing line."
My observation is that the "one-second" assumption isn't always observed.
mjkelso@earthlink.net (FLBiker) writes:
> This is probably a newbie question, but I'll throw it out there anyway...
>
> What are the specific rules for awarding finish times at the end of a stage? I know the peleton
> or, a bunch sprint, gets the same time at the line as the first person of the group to cross. But
> in the case of a strung out paceline or if you're in a smaller group off the back/front, how close
> do you have to be to the person in front of you to get the same time as them?
>
> I'm assuming, that, because the times go down to the second, you have to be within a second of the
> bike in front of you (??) or is it bike lengths or something else...?
If the peloton crosses the line en masse, they will all get the same time as the first rider
across the line.
But all the riders must have wheels overlapping when viewed from the side.
An extreme example will perhaps illustrate.
A peloton with 200 riders in it. The first rider croses the line in 4 hours even.
The next 99 riders all are overlqapped. IE: the front whell of any particular rider is ahead of the
back wheel of the rider in front. These guys all get 4h00.00 for their time. This hold true even
though the real time of finisher 100 might actually be 4:00.2999
Then the front wheel offinisher 101 is a few centimeters behind the back wheel of finisher 100. His
real time is 4:00.30 and this is the time he will get according to the rules. Should riders 102 to
200 be overlapped they will get 4:00.30.
But if any rider is not overlapped, he will be timed as was rider 101.
Now admittedly, this rule is flaunted more often than honoured a you will see if you watch the Tour
stage finishes.
But that is the way it is.
Le vent a Dos
--
Davey Crockett
"Davey Crockett" <DC@hotmail.com> wrote in message news:87ptjndat9.fsf@cpe0050da66e294-
> But all the riders must have wheels overlapping when viewed from the
side.
Is this in the rules (or the Tou or UCI)? If not, are you making it up?
JT
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peloton!!!! "FLBiker" <mjkelso@earthlink.net> wrote in message
news:19b80ea4.0308021145.789026a@posting.google.com...
> This is probably a newbie question, but I'll throw it out there anyway...
>
> What are the specific rules for awarding finish times at the end of a stage? I know the peleton
> or, a bunch sprint, gets the same time at the line as the first person of the group to cross. But
> in the case of a strung out paceline or if you're in a smaller group off the back/front, how close
> do you have to be to the person in front of you to get the same time as them?
>
> I'm assuming, that, because the times go down to the second, you have to be within a second of the
> bike in front of you (??) or is it bike lengths or something else...?
>
> John
"Davey Crockett" wrote:
> But all the riders must have wheels overlapping when viewed from the side.
and later "Davey Crockett" wrote:
> He is in a different bunch and it will have a different time from the rider perhaps only a half
> wheel or less in front of him.
Your two statements describe different things.
It seems to me that you're trying to obscure the fact that you don't actually know the rules and
rather than actually reading them you try to obscure the issue with high-falutin phrases like
"Whilst the national rules of different UCI member states."
Do your credibility a favor and show us the rule you are talking about from the UCI or the Tour de
France. If you can't, please don't bull**** us.
JT
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"John Forrest Tomlinson" <usenetremove@jt10000.com> wrote in message
news:84314734.0308030159.191a279e@posting.google.com...
[about Davey Crockett's two recent posts]
> Your two statements describe different things.
Sorry to respond to my own post, and most of all sorry for my comment above. I did not understand
what you were writing and now realize your two statements describe the same thing.
That said, I still do not believe you. and would appreciate your referring us to the rule you are
talking about from the UCI or Tour de France.
JT
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PelOton, pelOton....
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usenetremove@jt10000.com (John Forrest Tomlinson) writes:
> "John Forrest Tomlinson" <usenetremove@jt10000.com> wrote in message
> news:84314734.0308030159.191a279e@posting.google.com...
>
> [about Davey Crockett's two recent posts]
>> Your two statements describe different things.
>
> Sorry to respond to my own post,
Talking to yourself now dude? [Davey nudges Jim Bowie, they both laugh their Cocks off]
> and most of all sorry for my comment
Yeah. You're sorry to reveal what an AssHole you are to the whole newsgroup. dude, not for the
comment per se, Right?.
> I did not understand what you were writing
You never said a truer word dude.
> That said, I still do not believe you.
Please yourself dude. I could care less. After all, it's probably beyond my capabilities to change
the mind of a Wanker who probably still believes in Santa Klaus, God, the Tooth Fairy and that OJ
Simpson was innocent.
> and would appreciate your referring us to the rule you are talking about from the UCI or Tour de
> Frankreich
Try ICI 2.3.048 or the Tour Rules (Condensed into Article 14 for those too lazy or too stupid to
read the full version):
``Aux arrivees tous les coureurs d'un meme peloton sont credites du meme temps.''
``A CHAQUE COUPURE EFFECTIVE (Got that Wanker?) le chronometreur enregistre un nouveau temps.''
And for what it's worth, Wanker, if you'd queried the posts in a civilized, non argumentative
manner, you'd have got a polite reply.
But it's quite apparent to me that that would have been totally out of character.
~PLONK~ (That's HackerSpeak for ``You just made my KillFile''
--
le vent en Face et la Pompe dans votre Roue
Davey Crockett
"Davey Crockett" <DC@hotmail.com> wrote in message
news:877k5uamkp.fsf@cpe0050da66e294-cm0f2069983361.cpe.net.cable.roger
s.com...
>
>
> 'A CHAQUE COUPURE EFFECTIVE (Got that Wanker?) le chronometreur enregistre un nouveau temps.''
You've made a big assumption about what "coupure effective" means. In fact, you've made up your own
interepreation of that to mean wheels must overlap or else there is a gap.
Which is my point -- your interpretation of the rules (while common) is not actually the same thing
as the rules -- you're bull****ting about the rules.
It might be common practice in races, but at least from the evidence you present there is no such
rule that wheels must overlap for there not to be a gap.
JT
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"Davey Crockett" <DC@hotmail.com> wrote in message
news:877k5uamkp.fsf@cpe0050da66e294-cm0f2069983361.cpe.net.cable.rogers.com. ..
>
>
> And for what it's worth, Wanker, if you'd queried the posts in a civilized, non argumentative
> manner, you'd have got a polite reply.
>
> But it's quite apparent to me that that would have been totally out of character.
>
> ~PLONK~ (That's HackerSpeak for ``You just made my KillFile''
Dumbass -
JT didn't post anything that offensive. He said he didn't believe you.
If that's your standard for killfiling, you may have to block 75% of this group.
thin skin + rbr = aggravation
Davey Crockett <DC@hotmail.com> wrote in message >
> If the peloton crosses the line en masse, they will all get the same time as the first rider
> across the line.
>
> But all the riders must have wheels overlapping when viewed from the side.
>
> An extreme example will perhaps illustrate.
>
> A peloton with 200 riders in it. The first rider croses the line in 4 hours even.
>
> though the real time of finisher 100 might actually be 4:00.2999
>
> Then the front wheel offinisher 101 is a few centimeters behind the back wheel of finisher 100.
> His real time is 4:00.30 and this is the time he will get according to the rules. Should riders
> 102 to 200 be overlapped they will get 4:00.30.
>
> But if any rider is not overlapped, he will be timed as was rider 101.
Well, the only question I would have here is that times that are posted for the stage _only_ go down
to the 1 second resolution. So, I would think that rider 101, who is just a few centimeters off the
wheel of rider 100, would still actually get the same time, no?...(I'm also assuming your example
shows tenths of seconds...)
John
Originally posted by Flbiker
Davey Crockett <DC@hotmail.com> wrote in message >
> If the peloton crosses the line en masse, they will all get the same time as the first rider
> across the line.
>
> But all the riders must have wheels overlapping when viewed from the side.
>
> An extreme example will perhaps illustrate.
>
> A peloton with 200 riders in it. The first rider croses the line in 4 hours even.
>
> though the real time of finisher 100 might actually be 4:00.2999
>
> Then the front wheel offinisher 101 is a few centimeters behind the back wheel of finisher 100.
> His real time is 4:00.30 and this is the time he will get according to the rules. Should riders
> 102 to 200 be overlapped they will get 4:00.30.
>
> But if any rider is not overlapped, he will be timed as was rider 101.
Well, the only question I would have here is that times that are posted for the stage _only_ go down
to the 1 second resolution. So, I would think that rider 101, who is just a few centimeters off the
wheel of rider 100, would still actually get the same time, no?...(I'm also assuming your example
shows tenths of seconds...)
John
I might not fully understand you, but i will try to explain. If there is a gap (how this gap is judged i will not get into) then the riders in the new group get a new time for themselves. This new time is the ACTUAL time of the first rider. Therefore, if the first 100 riders are in the same group and if there is a 1 second split between the 100th and 101st rider the 100st rider will get his actual time. So in reality the first rider might have crossed at 4.00 the 100th at 4 hours 15 seconds and the 100st at 400.16. Nonetheless, the 100th rider would get a time of 4.00, but the 101st who would only be a second back of the 100th would get a time of 4 hours. This is somewhat unfair and thus leads to pretty generous rulings.
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