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10-06.-2008, 10:42 AM
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#16 |
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Re: metallurgy question
Michael Press wrote:
> In article <slrng4pnjh.5i0.spamspam@bowser.marioworld>, > Ben C <spamspam@spam.eggs> wrote: > >> On 2008-06-08, Michael Press <rubrum@pacbell.net> wrote: >> [...] >>> Elastic modulus is a 2-tensor of dimension 3. >>> 9 components. >>> The diagonal components give deformation normal to >>> a coordinate plane given force applied normal to >>> the coordinate planes. >>> The six off diagonal components give shear deformation >>> for force applied parallel to coordinate planes. >>> The 9 components could all be different from each other. >> So for a lump of steel, am I right in thinking the tensor looks like >> this: >> >> E 0 0 >> 0 E 0 >> 0 0 E >> >> where E is about 200GPa. >> >> But for CF or something anisotropic, I would have different values all >> over the place. >> >> There don't seem to be any "shear components" in my matrix for steel, >> but I don't really understand that: coordinate planes are usually >> orthogonal, which means force normal to one plane is parallel to the >> other two. So I don't see how you can divide forces into two sets of >> those normal to coordinate planes and those parallel to them. > > Epoxy resin and carbon fiber lay ups have anisotropic elastic properties, > as do various crystals. > > <http://books.google.com/books?id=90_ORVHeNkIC&pg=PT237&lpg=PT237&dq=anisotropic+crystal+%22elastic+modulus%22&source=web&ots=Zg1nRkq41y&sig=39g5dHxh5jGudvEd3_N-aug5sFc&hl=en> > so? that doesn't address his question in the slightest. perhaps you shouldn't try to bullshit outside your area of expertise? ah, but i remember now, you're the guy that thinks anodizing crack orientation has no bearing on fatigue initiation! now your confusion becomes clear! |
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