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#1 |
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Senior Member
Join Date: Jan 2002
Location: Vanderbijlpark, South Africa
Posts: 204
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How does one calculate the % incline during a ride. During the Tour you heard that they were doing a 10% climb over 2km, etc. How does this work?
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#2 | ||
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Guest
Posts: n/a
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Quote:
Go buy a Heat rate moitor with altituds sensor eg(Polar S710 ) and buy me on too ![]() Quote:
It means the average gradient of that 2k climb was 10%. |
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#3 |
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Senior Member
Join Date: Jan 2002
Location: Vanderbijlpark, South Africa
Posts: 204
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Got a S720. It does not give you the average climbed. How do you calculate the 10% avg. Do I take the mtrs. climbed/distance or distance/mtrs climbed?
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#4 |
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Guest
Posts: n/a
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Good question.............. ???
Climb length = 12km alt gained = 800m Would this be a 6.6% gradient? |
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#5 |
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Registered User
Join Date: Jan 2002
Location: Johannesburg, South Africa
Posts: 830
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Steve - quite right.
Gradient is calculated: height gained (vertical) / distance ridden (horizontal). It's a percentage so don't forget to multiply by 100... Ewep: 10% for 2km would be a 200m gain in vertical height (doesn't sound like a lot but 10% is an evil gradient). 10% = 200m/2000m |
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#6 |
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Registered User
Join Date: Jun 2002
Location: Bathurst, NSW, Australia
Posts: 327
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I have also wondered this for quite a while........i understand the "altitude gained" part of the equation, but is the "distance covered"=distance on the road, or horizontal distance?
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#7 | |
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Guest
Posts: n/a
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Quote:
Formula for gradient = dy/dx ; which are perpendicular measurements, therefore: gradient equals (change in vertical height) divided by (change in horizontal distance). But it doesn't really make that much difference for small angles like 10%. See what I mean by drawing a 90° triangle with a 10cm horizontal base and 1cm vertical height. Measure the hypotenuese (diagonal) and compare it to the 10cm base. * ![]() |
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#8 |
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Guest
Posts: n/a
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To figure grade percentages:
http://www.computrainer.com/images/grade.jpg |
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