A
Ambrose Nankive
Guest
In news:[email protected],
Dr Curious <[email protected]> typed:
> "Doctor J. Frink" <[email protected]> wrote in
> message news:[email protected]...
>> On Tue, 15 Jun 2004 13:45:16 +0100, Dr Curious
>> <[email protected]> wrote:
>>> So the outside circumference of an inflated tyre is
>>> larger than that of a flat tyre is it?
>>>
>>> Curious
>>
>> Take bike.
>>
>> Deflate front tyre.
>>
>> Wheel descends to floor to rest on rim.
>>
>> Note distance r_flat from hub to floor (ie the radius of
>> the circle that we would be rolling on).
>>
>> Pump up tyre.
>>
>> Wheel rises from floor as tyre inflates.
>>
>> Note distance r_inflated from hub to floor (ie the radius
>> of the circle that we would be rolling on).
>>
>> You'll find that r_inflated > r_flat.
>>
>> The actual circumference of the tyre itself may not
>> change but the effective wheel radius does, and that's
>> what we're really measuring (ok, labelling it
>> Circumference wasn't totally accurate but it's close
>> enough).
> I'm sorry but this all totally irrelevant.
>
> The radius of the wheel is irrelevant.
>
> When a tire is flat, all this means is that the wheel/tyre
> is no longer circular. It's now a part circle with a flat
> at the bottom. And so there's more surface area in contact
> with the ground. But the actual outside circumference
> remains exactly the same. It wouldn't even matter if you
> were riding on oval wheels. All you ever need measure are
> the number of revolutions multiplied by the circumference
> of the tyre.
The thing is that the squashing causes the tyre to slip
slightly, so it does actually follow the path of a circle of
the effective radius of the wheel. So it's not irrelevant.
In general it's better to be right before you call other
people's reasoning irrelevant.
A
Dr Curious <[email protected]> typed:
> "Doctor J. Frink" <[email protected]> wrote in
> message news:[email protected]...
>> On Tue, 15 Jun 2004 13:45:16 +0100, Dr Curious
>> <[email protected]> wrote:
>>> So the outside circumference of an inflated tyre is
>>> larger than that of a flat tyre is it?
>>>
>>> Curious
>>
>> Take bike.
>>
>> Deflate front tyre.
>>
>> Wheel descends to floor to rest on rim.
>>
>> Note distance r_flat from hub to floor (ie the radius of
>> the circle that we would be rolling on).
>>
>> Pump up tyre.
>>
>> Wheel rises from floor as tyre inflates.
>>
>> Note distance r_inflated from hub to floor (ie the radius
>> of the circle that we would be rolling on).
>>
>> You'll find that r_inflated > r_flat.
>>
>> The actual circumference of the tyre itself may not
>> change but the effective wheel radius does, and that's
>> what we're really measuring (ok, labelling it
>> Circumference wasn't totally accurate but it's close
>> enough).
> I'm sorry but this all totally irrelevant.
>
> The radius of the wheel is irrelevant.
>
> When a tire is flat, all this means is that the wheel/tyre
> is no longer circular. It's now a part circle with a flat
> at the bottom. And so there's more surface area in contact
> with the ground. But the actual outside circumference
> remains exactly the same. It wouldn't even matter if you
> were riding on oval wheels. All you ever need measure are
> the number of revolutions multiplied by the circumference
> of the tyre.
The thing is that the squashing causes the tyre to slip
slightly, so it does actually follow the path of a circle of
the effective radius of the wheel. So it's not irrelevant.
In general it's better to be right before you call other
people's reasoning irrelevant.
A