One is to break one hour on Mt. Diablo in Northern California (South Gate).

It seems people analyzing pro climbing performances have used a formula to estimate watts/kg.

Relative power (W/kg) = VAM (m/hour) / (Gradient factor x 100)

Gradient factor = 2+(percentage grade/10), so 6% would be 2.6

Since Mt. Diablo is over an hour from where I live, I was hoping to use this to guesstimate what watts/kg I will need (and I am intersted what folks think of the formula, which could be useful for estimating requirements for hills outside your area).

So, if the climb is 11.3 miles at 5.8% average, it is 981.5m to the top. If the goal is just under an hour, I need to climb at least 982m/h.

According to the above formula:

982/((2+0.58)*100)= ~3.8w/kg. Honestly that does not seem too hard, though I am not sure I can do that for an hour at the moment.

I have not gone all out recently (trying to get lots of SST in), but I did do a recent effort on a 3.3 mile, 7.3% hill (Old la Honda) in a group so I went a bit harder than normal and did 21 minutes, so more like:

VAM:393/(21/60)= 1123

1123/273= 4.11 watts/kg

My feeling is that breaking one hour on Diablo is more of a challenge than this or even breaking 20 minutes on Old la Honda (I did just under 20 a few years ago when I was slimmer). If this math is correct, though, that should not be the case and my goal should be attainable now?

Any views on this formula or the watts/kg required for Diablo?

Thanks!