Running one 10-min. mile while pushing a 60-lb. stroller will burn off
exactly 127.64 calories (assuming body weight of 125 lbs., ambient air
temperature of 70 degrees F, 0% grade, relative humidity of 46.3
percent and winds of 4.8 mph or less, unless they are from the
northwest, in which case calories burned will be 128.12). For every
pound of body weight over 125, add 13.647 calories. For every pound
under 125, subtract 18.982 calories. Add 1.33 calories for each
1-degree temperature increase over 70. Subtract 1.67 calories for each
temperature decrease of 1 degree. For each percentage point of
relative humidity over the 46.3 percent base, add 0.79 calories. For
each percentage point under 46.3 percent, subtract 0.58 calories. With
an 11-min. mile, use the above formula starting with a base of 124.21
calories.
Not knowing your route, I cannot predict calorie reduction owing to
changes in surface incline. However, assuming for the sake of
argument that half your route is at a 2% uphill grade and half is at a
2% downhill grade, calorie reduction owing to these factors will be
negligible, i.e., in the 1.5-to-1.75 calorie range. If you will
calculate the exact grade and length of any hills on your route (both
up and down), I'll run the numbers and tell you exactly how they
affect calorie-reduction.
Hope this helps.
I have not accounted for hair-related wind resistance, as I don't know
the length or thickness of your hair. Calorie reduction will also
vary somewhat based on the size and weight of your shoes as well as
the relative lightness (of weight AND color) of the clothes you wear
while running.
"Linda and Pete" <
[email protected]> wrote in message news:<
[email protected]>...
> Here I am again - Ms. Curious. Anyway know a way to find out how many
> calories are burned say running a 10 min mile with a double jogging
> stroller - say pushing 60 lbs? Just curious - recently been trying to get
> more running in and the only way to do it is to bring my twin toddlers - not
> easy but at least it's something. Actually, it's probably more like an 11
> min mile. Thanks, Linda