F
Fbloogyudsr
Guest
"Ian St. John" <[email protected]> wrote
> "fbloogyudsr" <[email protected]> wrote
> > No. You are wrong.
>
> False. You are a smart idiot, I will admit.
Interesting. I write a very correct description, and you have to use insults to attempt to
refute it.
> > Theoretical energy efficiency in a closed system
>
> The system is not closed.
*IF* the mine - and Earth's radioactively heated core - is not considered part of the system it
isn't. But I don't see how you can say that when the heat transfer coil is down there.
> > is defined as:
> >
> > E = (Ti - Tf) / Ti,
> >
> > Where Ti is initial temperature, Tf is final temperature. But, you have to remember that these
> > temperatures are defined in degrees absolute. You can only get efficiencies of 1 if you have a
> > heatsink at zero
> absolute.
> > You can never go above 1 - 2nd law of thermodynamics.
>
> Not applicable. You are moving heat from OUTSIDE which is by definition
not
> a closed system.
>
> >
> > Heat pumps are definitely more efficient than other forms of heating and cooling, but are *NOT*
> > zero-cost, which is what E of 1 means.
>
> Nobody said they were. What is said is that for every BTU of electical energy they can deliver
> three to fifty BTUs of heat. Heavily depending on the exact nature of the source and the
> temperature difference. For mine water at 100 meters and 18C it can deliver more than ten BTUs
> for every
btu
> of electicity.
Yeah, I know that. So what? Your use of the term "efficiency" is incorrect, because, by any
reasonable scientific method, you must include the mine in the system and calculation of efficiency.
By not doing so, you are just using junk science.
FlodR
> "fbloogyudsr" <[email protected]> wrote
> > No. You are wrong.
>
> False. You are a smart idiot, I will admit.
Interesting. I write a very correct description, and you have to use insults to attempt to
refute it.
> > Theoretical energy efficiency in a closed system
>
> The system is not closed.
*IF* the mine - and Earth's radioactively heated core - is not considered part of the system it
isn't. But I don't see how you can say that when the heat transfer coil is down there.
> > is defined as:
> >
> > E = (Ti - Tf) / Ti,
> >
> > Where Ti is initial temperature, Tf is final temperature. But, you have to remember that these
> > temperatures are defined in degrees absolute. You can only get efficiencies of 1 if you have a
> > heatsink at zero
> absolute.
> > You can never go above 1 - 2nd law of thermodynamics.
>
> Not applicable. You are moving heat from OUTSIDE which is by definition
not
> a closed system.
>
> >
> > Heat pumps are definitely more efficient than other forms of heating and cooling, but are *NOT*
> > zero-cost, which is what E of 1 means.
>
> Nobody said they were. What is said is that for every BTU of electical energy they can deliver
> three to fifty BTUs of heat. Heavily depending on the exact nature of the source and the
> temperature difference. For mine water at 100 meters and 18C it can deliver more than ten BTUs
> for every
btu
> of electicity.
Yeah, I know that. So what? Your use of the term "efficiency" is incorrect, because, by any
reasonable scientific method, you must include the mine in the system and calculation of efficiency.
By not doing so, you are just using junk science.
FlodR