looks like about 8%Jaguar27 said:OK, I know I'm stoopid...but...
If I ride .217 miles and gain 95 feet, what would the % be?
Thanks for your help!!
Eden said:looks like about 8%
convert miles to feet then divide rise by run, convert to percentage
so
.217 miles = 1,145.76 feet (used and online converter)
95/1,145.76 =.083 = 8.3%
Chase. Chevy. Gerald Ford.Chance3290 said:Ah, it was my understanding that there would be no math involved in this forum.
Scarpelli said:The trick is to climb an 8% grade at a fast enough pace that the atmospheric pressure drops quickly enough to make your ears pop.
This feat gets harder and harder every year...
Eden said:looks like about 8%
convert miles to feet then divide rise by run, convert to percentage
so
.217 miles = 1,145.76 feet (used and online converter)
95/1,145.76 =.083 = 8.3%
Now for the real math lesson. There was a similar thread a while back, where it was pointed out that there is a difference between the true run and the measured distance traveled. This is a good example of why, at the grades most people can climb, it does not make any difference.Chance3290 said:Ah, it was my understanding that there would be no math involved in this forum.
RickF said:Now for the real math lesson. There was a similar thread a while back, where it was pointed out that there is a difference between the true run and the measured distance traveled. This is a good example of why, at the grades most people can climb, it does not make any difference.
The true grade is the rise divided by the run, as Eden correctly stated. The rise is 95 feet. The distance you traveled is the hypotenuse. The run would be the third leg of the triangle that connects the starting point to the point 95 feet below the finishing point. If you traveled 0.217 miles, that is 1,145.76 feet (again, as correctly stated by Eden), but the run is only 1141.81 feet (the square root of (1145.76 feet squared minus 95 feet squared)). Thus, the "true" grade is 8.32009% instead of 8.29144%.
Other than geometry teachers, would anyone care about a difference that small? Now, if you were able to climb a 45 degree incline (100% grade), the difference between using the actual distance traveled rather than the true run is big. Using the distance traveled, you would calculate the grade as 70.07107%, but it is really 100.00000%.
End of math lesson - back to cycling.
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