- Jul 4, 2003
Tom Anhalt said:Here's the way I think of it: TSS isn't "additive" over segments because the total NP is not equivalent to the average of the NPs of the segments.
This is because taking the "4th root of the average of the sum of the powers^4" over the whole range is NOT equivalent to the average of the sum of any subsets of "4th root of the average of the sum of the powers^4". For example:
(( a^4 + b^4 + c^4 + d^4)/4 )^0.25 does NOT = (((a^4 + b^4)/2)^0.25 + ((c^4 + d^4)/2)^0.25)/2
Since TSS is calculated from the NP, FTP and time....you can see that the only way TSS could be "additive" is if the NP of the whole ride was equal to the average of the NP of the segments. Make any sense?
Yes, which is why I replied to beerco as I did (think about it).