Joe Riel said:Quoted message said:Quoted message said:Well, a quick back of the email calculation shows that for a bike and
rider weighing 1000N (225lbs) and a 10% grade, maximum energy
dissipation by the brakes will occur at a speed of around 50 km/h. At
that speed the bike is losing gravitational potential energy at a rate
of 1388 watts and it is taking 465 watts for wind and rolling
resistance, so that leaves 923 watts for the brakes to get rid of. If
we are using only one brake that is 923 watts into a 450 gm piece of
Al with a surface area of a few hundred cm^2. I suspect it could get
pretty hot.Hold the phone! I'll propose that the rim will get hotter at 1/10
that speed because there is practically no convection cooling when
riding slowly. Convection is the primary coolant of rims in the
absence of rain water. Besides, the rate of conversion of kinetic
energy to heat increases with speed until the brake pad fails. Where
do you get 50km/h?
Quoted message said:I should let Jim respond, but from my post it is clear that this
is the speed that maximizes the power dissipation in the brakes.
You are assuming constant speed braking rather than braking for
hairpin turns at the end of free rolling straights. My experience is
that the tube is well insulated by the tire and that heat comes in
mostly by contact with the rim (strip).
Quoted message said:As you suggest, this may not be the worst-case for rim temperature.
Quoted message said:What's a reasonable model for convection losses vs speed?
I have no idea. I'm sure there is data on wind speed air temperature
and heat transfer, but that requires a known rim temperature and
speed. As I said, steep slow descents are the bane of tires. These
are where I've seen the blowouts.
Jobst Brandt
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