On 2007-06-03, TimC (aka Bruce)
was almost, but not quite, entirely unlike tea:
Quoted message said:On 2007-06-02, Zebee Johnstone (aka Bruce)
was almost, but not quite, entirely unlike tea:
Quoted message said:In aus.bicycle on Sat, 02 Jun 2007 13:25:23 GMT
PeteSig said:Incidentally, does your recumbent have a smaller front wheel (eg 20"😉 I'm
not sure about the physics of it but I do believe discs should be more
effective on a small wheel than a 26" as they are proportionally bigger
compared to the rim. Thus greater braking leverage. Someone here will tell
me if I'm wrong or not.
It's a 20" front. No idea about the physics but it does seem
intuitively likely.
Whoops, forgot to look at the disk brake situation. Anyway, rim
brakes:
Quoted message said:Torque is decreased at the hub because of the smaller radius, but
that's irrelevant because that torque has to be converted back to a
linear force at the bottom of the wheel. Think of the brake as being
some kind of linear brake that is sitting some distance off the
ground. It makes no difference if it is 20" or 26" off the ground,
the same lateral force is being applied.
I think.
So no change for small vs large.
And disk brakes:
For a given force on the disks, you get a given torque. Torque is
force multiplied by radius, so the linear force is going to increase
because of the smaller radius.
Damn, your intuition is better than mine. I blame the lack of coffee.
Damn weekends, I don't get to drink coffee for 2 days in a row.
--
TimC
Just keep in mind that when you are using TRANSFER, you are not
programming, but hacking. All else follows logically from this
premise, Grasshopper. -- James Van Buskirk in comp.lang.fortran