remove the polite word to reply said:the steeper the slope the less that drafting gives you
hope because effort spent overcoming wind resistance
varies inversely with steepness as a % of total effort
I know, as does only a true bucket of lard who cannot cope
Not quite.....
Consider "effective grade" equals the sum of grade and
coefficient of rolling resistance. Then, in the steep limit,
speed is inversely proportional to effective grade. The
standard model is that wind resistance force is proportional
to speed squared, and therefore power dissipated to wind
resistance is proportional to speed cubed, or inversely
proportional to effective grade cubed.
A more complete model recognizes, for no wind:
1 = (v/v0)^3 + geff v/vclimb
vclimb is the max vertical climb rate, geff is the effective
grade, v0 is the max speed w/ geff = 0. (this is a nice form
of the power-speed eqn, as it involves easily estimatable
quantities)
This cubic equation, for significant hills, can be
iteratively solved fairly easily:
v (next iteration) = (1 - (v/v0)^3) (vclimb/geff) (previous
iteration)
With an initial guess v = 0.
Dan