D
Douglas Landau
Guest
Jay Hill <[email protected]> wrote in message news:<[email protected]>...
> Douglas Landau wrote:
> >
> > How much footprint there is depends upon the PSI to
> > which the tire is inflated, not how stiff it is. If the
> > tires are inflated to 20PSI, and the bike+rider weigh
> > 200 lbs, then the tires are going to lay down ten square
> > inches of rubber, no matter what.
> >
> So one of my car tires, which are about 10" wide, will
> leave the same footprint as one of my 700c x 23mm bike
> tires if they're both inflated to the same psi & have the
> same weight pressing down on them?
Sure, at least in the clean case. I admit that not all cases
are clean. In fact, the case in which I frst read what I was
quoting is itself not clean.
What I wrote, I quoted straight from "the Boonie Book", a
book about dirtbiking from the 70s which I had when I was a
kid. The author said that about dirtbike tires, addressing
the issue of whether a rider riding sideways across a slope
should weight the uphill peg or the downhill peg for best
traction. The author claimed that it does not matter, and
that was his reasoning.
However, I say that in fact, if you park your dirtbike on
clean rock, you will see that in fact only a few knobs of
each tire are touching the rock, nowhere near the number
of square inches of rubber which should be according to
the theory.
So, the contactPatch=Load/PSI formula is too simplistic to
be absolutely correct. Bacardi is right, to some extent. I
should have truncated the "no matter what". That said, the
case of roadbike tires is a pretty clean case.
Doug
> Douglas Landau wrote:
> >
> > How much footprint there is depends upon the PSI to
> > which the tire is inflated, not how stiff it is. If the
> > tires are inflated to 20PSI, and the bike+rider weigh
> > 200 lbs, then the tires are going to lay down ten square
> > inches of rubber, no matter what.
> >
> So one of my car tires, which are about 10" wide, will
> leave the same footprint as one of my 700c x 23mm bike
> tires if they're both inflated to the same psi & have the
> same weight pressing down on them?
Sure, at least in the clean case. I admit that not all cases
are clean. In fact, the case in which I frst read what I was
quoting is itself not clean.
What I wrote, I quoted straight from "the Boonie Book", a
book about dirtbiking from the 70s which I had when I was a
kid. The author said that about dirtbike tires, addressing
the issue of whether a rider riding sideways across a slope
should weight the uphill peg or the downhill peg for best
traction. The author claimed that it does not matter, and
that was his reasoning.
However, I say that in fact, if you park your dirtbike on
clean rock, you will see that in fact only a few knobs of
each tire are touching the rock, nowhere near the number
of square inches of rubber which should be according to
the theory.
So, the contactPatch=Load/PSI formula is too simplistic to
be absolutely correct. Bacardi is right, to some extent. I
should have truncated the "no matter what". That said, the
case of roadbike tires is a pretty clean case.
Doug