On Fri, 19 Nov 2004 18:20:08 -0500, [email hidden]
(Chris Zacho 'The Wheelman') said:[email hidden] (David Wagner) wrote,
Quoted message said:I would think that the weight load of the
bicycle is transferred from the frame to
the hubs, and then through the hub to
the *upper spokes* to the top of the rim
via tensile forces, and then from the top
of the rim to the bottom of the rim --- the
rim being held in shape by the spokes
through tension---and then to the tires
and the ground. Isn't this the correct
view?
You are correct. A spoked wheel is, as one engineer put it "A suspension
bridge with no end points. ALL the spokes support the hub in the center
of an evenly tensioned circular "Bridge". However, the spokes on the
upper half do bear slightly more of the load, gradually increasing the
closer to the zenith (top) you get.
Just look at how there are designed to attach to the wheel and hub.
Every spoke is designed to resist tension (pulling away), not
compression (pressing together), as would be encountered at the bottom
of the wheel.
- -
"May you have the wind at your back.
And a really low gear for the hills!"
Chris Zacho ~ "Your Friendly Neighborhood Wheelman"
Chris'Z Corner
http://www.geocities.com/czcorner
Dear Chris,
"However, the spokes on the upper half do bear slightly more
of the load, gradually increasing the closer to the zenith
(top) you get."
I'm trying to understand what you're saying in relation to
the "Post-Processing" table for the projected spoke tension
changes here:
http://www.achrn.demon.co.uk/astounding/ian/wheel/index.html
But I'm not even sure which column you would be looking at.
Are you talking about raw tension change (the "Tension"
column), the calculated vertical force of such changes with
the spoke angle considered (the "vertical force" column), or
something not shown here, or even something that contradicts
this kind of analysis?
That is, what tension changes or vertical lift (or what)
should I see in a 36-spoke wheel with a 1,000 newton load?
Carl Fogel